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# Aptitude Questions and Answers with Explanation for placement, MBA

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 21 Arun obtained 76, 65, 82, 67 and 85 marks (out in 100) in English, Mathematics, Chemistry, Biology and Physics. What is his average mark? A. 53 B. 54 C. 72 D. 75
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Explanation

Average mark = (76+65+82+67+85)/5 = 375/5 =75.

 22 Distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of the train during the whole journey? A. 69.0 km /hr B. 69.2 km /hr C. 67.2 km /hr D. 67.0 km /hr
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Explanation

If a car covers a certain distance at x kmph and an equal distance at y kmph. Then,

average speed of the whole journey = 2xy/(x+y) kmph.

By using the same formula, we can find out the average speed quickly.

Average speed :-

=> 2×84×56/(84+56)

=> 2×84×56/140

=> 2×21×56/35

=> 2×3×56/5

=> 336/5

=> 67.2.

 23 The average age of 36 students in a group is 14 years. When teacher's age is included to it, the average increases by one. Find out the teacher's age in years? A. 51 years B. 49 years C. 53 years D. 50 years
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Explanation

average age of 36 students in a group is 14
Sum of the ages of 36 students = 36 × 14
When teacher's age is included to it, the average increases by one
=> average = 15
Sum of the ages of 36 students and the teacher = 37 × 15
Hence teachers age :-
= 37 × 15 - 36 × 14
= 37 × 15 - 14(37 - 1)
= 37 × 15 - 37 × 14 + 14
= 37(15 - 14) + 14
= 37 + 14
= 51

 24 The average of five numbers id 27. If one number is excluded, the average becomes 25. What is the excluded number? A. 30 B. 40 C. 32.5 D. 35
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Explanation

Sum of 5 numbers = 5 × 27
Sum of 4 numbers after excluding one number = 4 × 25
Excluded number
= 5 × 27 - 4 × 25
= 135 - 100 = 35

 25 The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. Find out the highest score of the player. A. 150 B. 174 C. 180 D. 166
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Explanation

Total runs scored by the player in 40 innings = 40 × 50

Total runs scored by the player in 38 innings after excluding two innings = 38 × 48

Sum of the scores of the excluded innings = 40 × 50 - 38 × 48 = 2000 - 1824 = 176

Given that the scores of the excluded innings differ by 172. Hence let's take

the highest score as x + 172 and lowest score as x.

Now x + 172 + x = 176.

=> 2x = 4.

=> x =4/2 = 2.

Highest score = x + 172 = 2 + 172 = 174.

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